(x^2-4x+3)/(x^2-6x+8)=-1

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Solution for (x^2-4x+3)/(x^2-6x+8)=-1 equation: 



(x^2-4x+3)/(x^2-6x+8)=-1

We move all terms to the left:

(x^2-4x+3)/(x^2-6x+8)-(-1)=0



Domain of the equation: (x^2-6x+8)!=0

We move all terms containing x to the left, all other terms to the right

x^2-6x!=-8

x∈R



We add all the numbers together, and all the variables

(x^2-4x+3)/(x^2-6x+8)+1=0

We multiply all the terms by the denominator


(x^2-4x+3)+1*(x^2-6x+8)=0

We get rid of parentheses

x^2-4x+1*(x^2-6x+8)+3=0

We move all terms containing x to the left, all other terms to the right

x^2-4x+1*(x^2-6x+8)=-3

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